Home Posts Sh \[\mathop {\lim }\limits_{x \to \infty } \sqrt {{b^2} - 4ac} \sqrt {{b^2} - 4ac} \frac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}\] \[\sqrt {{a^2} + {b^2}} \mathop {\lim }\limits_{x \to \infty } \sqrt {{b^2} - 4ac} \frac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}\]
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